用Newtonsoft.Json 如何对JObject对象中的值进行排序

无奇龙

如下面的JSON字符串（只复制一个第一层子节点（以activity为根节点）），解析以后竞有5层，模索很久才会通过遍历找到指定goodsCode值，现在想按,"time“作为关键字对第一层子节点排序，实在想不到办法，不会用OrderBy，哪个大神能贴出一下示例代码
{"activity":[{"channel":"MAF_OD","code":"1141","endDate":{"date":14,"day":0,"hours":10,"minutes":59,"month":8,"nanos":0,"seconds":59,"time":1410663599000,"timezoneOffset":-480,"year":114},"id":0,"name":"9月14日手机一元秒杀9点场 ","seckillFold":"null","seckillSettingDtos":[{"goodsCode":48754801,"goodsName":"界江梅花鹿双宝鹿茸+鹿鞭10克","goodsPrice":82,"goodsPriceStr":"82.00","id":0,"listingId":487548,"seckillInfoCode":"1141","seckillPrice":1,"seckillPriceStr":"1.00","seckillRate":1,"sellLimitFlag":1,"sellStorageNum":20,"storageNum":20,"storeId":3082},{"goodsCode":36658802,"goodsName":"城口老腊肉麻辣腊肉丝120g","goodsPrice":35,"goodsPriceStr":"35.00","id":0,"listingId":366588,"seckillInfoCode":"1141","seckillPrice":1,"seckillPriceStr":"1.00","seckillRate":1,"sellLimitFlag":1,"sellStorageNum":20,"storageNum":20,"storeId":3018}],"sellTime":{"date":14,"day":0,"hours":10,"minutes":59,"month":8,"nanos":0,"seconds":59,"time":1410663599000,"timezoneOffset":-480,"year":114},"startDate":{"date":14,"day":0,"hours":9,"minutes":0,"month":8,"nanos":0,"seconds":0,"time":1410656400000,"timezoneOffset":-480,"year":114},"title":"9月14日手机一元秒杀9点场 ","type":1}]}

站长苏飞

无奇龙 发表于 2014-9-14 12:24
我就是要对对象的排序方法，直接对这个字符串排序肯定没意思呀

对象里面不是List吗，这个随便写个排序就行了吧，比较冒泡，或者是二叉都行，

我的意思就是把转好的List的对象，进行一个排序，然后再转为Json就达到的效果，

我那里有说让你对字符串排序了，

站长苏飞

转成对后排序再转成Json，没有直接排序的方法

无奇龙

站长苏飞 发表于 2014-9-14 12:20
转成对后排序再转成Json，没有直接排序的方法

我就是要对对象的排序方法，直接对这个字符串排序肯定没意思呀

无奇龙

站长苏飞 发表于 2014-9-14 12:27
对象里面不是List吗，这个随便写个排序就行了吧，比较冒泡，或者是二叉都行，

我的意思就是把转好的Li ...

   JObject temp = JObject.Parse(html);

                    List<JToken> list1 = new List<JToken>();
                    list1=  temp["activity"].ToList() ;
            

                    IEnumerable<JToken> query = list1.OrderBy(JToken => JToken["startDate"]["time"]);
                    list1 = query.ToList();
感谢您的无私奉献，真是帮了我的大忙了